1.

Masses of three wires of copper are in the ratio 1 : 3 : 5and their lengths are in the ratio 5 : 3 : 1 The ratio of their electrical resistance are

Answer»

`1:15: 125 `
`1:3:5 `
`125: 15:1 `
`5:3:1 `

Solution :`Ralpha(1)/(A) ,m = rho v= rho .AL`
` R ALPHA(1)/(A ), alpha (I^2)/(m)`


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