Saved Bookmarks
| 1. |
Match Column -I with Column -II : Column -IColumn-II (A) Probability of survival of a radioactive nucleusfor one mean life( p ) N_(o)( 2) ^(-n) (B) Amount remaining after n-half lives( q)""_(o)lambda(t_(1) - t_(2)) ( C ) ( R_(2))/( R_(1)) , R_(1) =rate at time t_(1) R_(2)= rate at time t_(2)( r ) ((1)/( 2))^(11//10) (D) Amount left on 11^(th) day, starting with 1 mol of A ( t_(1//2) = 10 days )( s ) ( 1)/( e) |
|
Answer» |
|