Match List I with List II and select the correct answer using the code given below the lists : {:("List-I","List-II"),((A)"For ionic solid"r_+/r_(-)=0.51,(p)"Anion-anion contact present, cation lies in octahedral void"),((B)"For ionic solid"r_+/r_(-)=0.414,(q)"Anion-anion contact missing, cation lies in tetrahedral void"),((C )"For ionic solid"r_+/r_(-)=0.4,(r)"Anion-anion contact missing, cation lies in cubical void"),((D)"For ionic solid"r_+/r_(-)=0.9,(s)"Anion-anion contact missing, cation lies in octahedral void"):}

Match List I with List II and select the correct answer using the code

1.	Match List I with List II and select the correct answer using the code given below the lists : {:("List-I","List-II"),((A)"For ionic solid"r_+/r_(-)=0.51,(p)"Anion-anion contact present, cation lies in octahedral void"),((B)"For ionic solid"r_+/r_(-)=0.414,(q)"Anion-anion contact missing, cation lies in tetrahedral void"),((C )"For ionic solid"r_+/r_(-)=0.4,(r)"Anion-anion contact missing, cation lies in cubical void"),((D)"For ionic solid"r_+/r_(-)=0.9,(s)"Anion-anion contact missing, cation lies in octahedral void"):}
Answer» Solution :`0.225 le r_+/r_- lt 0.414 " " "CATION is in tetrahedral VOID" " " 0.732 le r_+/r_- lt 1` cubical void `0.414 le r_+/r_- lt 0.732` Cation is in octahedral VOIDS