1.

Match the element in column A with thevalency exhibited by the element given in column B{:(,"Column A",,,"Column B"),((A),"Neon",(),(a),""4),((B),"Oxygen",(),(b),""3),((C),"Potassium",(),(c),""2),((D),"Boron",(),(d),""1),((E),"Silicon",(),(d),""0):}

Answer»

`ATOB,"" Btoc," " Ctod, " " Dtoe," " Etoa`
`Atob,"" Btoc," " Ctoa, " " Dtoe," " Etod`
`Atoe,"" Btod," " Ctoa, " " Dtob," " Etoc`
`Atoe,"" Btoc," " Ctod, " " Dtob," " Etoa`

Solution :`Atoe`
Atomic NUMBEROF neon is 10 and electronic configuration 2 , 8 valency is zero.
`Btoc`
Atomic numberof oxygen is 8 and electronic configuration 2 , 6 valency= 8 - 6 = 2
`Cto d`
Atomic number of potassium is 19AND electronic configuration is 2 , 8 , 8 ,valency = 1
`Etoa`
Atomic number of SILICON is 14 and electronic cofiguration is 2 , 8 , 4 valency = 4


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