Match the entries of column I with appropriate entries of column II and choose the correct option out of the four options given. {:("Column I (Solutions mixed)","Column II (Noramolity after mixing)"),("(A) 100 cc of 0.2 N"H_(2)SO_(4)+" 100 cc of 0.1 N HCl","(p) 0.25 N"),("(B) 100 cc of 0.2 M "H_(2)SO_(4)+" 100 cc of 0.1 M HCl","(q) 0.067 N"),("(C) 100 cc of 0.1 M "H_(2)SO_(4)+" 100 cc of 0.1 M NaOH","(r) 0.15 N"),("(D) 100 cc of 0.1 M HCl "+" 50 cc of 0.2 N NaOH","(s) 0.05"):}

Match the entries of column I with appropriate entries of column II an

1.	Match the entries of column I with appropriate entries of column II and choose the correct option out of the four options given. {:("Column I (Solutions mixed)","Column II (Noramolity after mixing)"),("(A) 100 cc of 0.2 N"H_(2)SO_(4)+" 100 cc of 0.1 N HCl","(p) 0.25 N"),("(B) 100 cc of 0.2 M "H_(2)SO_(4)+" 100 cc of 0.1 M HCl","(q) 0.067 N"),("(C) 100 cc of 0.1 M "H_(2)SO_(4)+" 100 cc of 0.1 M NaOH","(r) 0.15 N"),("(D) 100 cc of 0.1 M HCl "+" 50 cc of 0.2 N NaOH","(s) 0.05"):}
Answer» A-r, B-s, C-p, D-q A-q, B-p, C-r, D-s A-r, B-p, C-s, D-q A-s, B-r, C-p, D-q Solution :A. `"100 cc of 0.2 N "H_(2)SO_(4)=100xx"0.2 meq"` = 20 meq `"100 cc of 0.1 HCL "=100xx0.1" meq = 10 meq"` Total meq = 30, Total volume = 200 cc `therefore"Noramality"=("30 meq")/("200 cc")="0.15 N"` B. `"100 cc of 0.2 M "H_(2)SO_(4)=100xx"0.2 mmol"` = 20 mmol = 40 meq `"1000 cc of 0.1 M HCl "=100xx0.1" mmol"` 10 m MOL = meq `"Normality "=("50 meq")/("200 cc")="2.25 N"` C. `"100 cc of 0.1 M "H_(2)SO_(4)="10 mmol = 20 meq"` `"100 cc of 0.1 M NaOH = 10 mmol = 10 meq"` `"10 meq NaOH will neutralize 10 meq of "H_(2)SO_(4)` `H_(2)SO_(4)" left = 10 meq, Total volume = 200 cc"` `therefore"Noramality "=("10 meq")/("200 cc")=0.05N.` D. `"100 cc of 0.1 N HCl = 10 meq"` `"50 cc of 0.2 N NaOH = 10 meq"` `"10 meq of HCl will completely neutralize 10 meq of NaOH"` `"NACL formed in the solution = 10 meq"` Normality of NaCl in the solution `= ("10 meq")/("150 cc")=0.067 N`