1.

Match the following

Answer»


Solution :A ) ` alpha = ` degree of ionization `=("Equivalent conductance at concentration C ")/("Equivalent conductance at Infinite dilution") =(^^_e^(c))/(^^_c^(0))`
B) `t_(+)` (Transport number ) Transport number of ION of elctrolyte in a solution is the FRACTION of TOTAL current carried by that ion in solution
` t_("ion") = ("current carried by an ion")/("total current carried by both ions")=(U^(+))/(U^(+) + U^(-))`
`t_("cation(+)") = ("current carried by an ion")/("current carried by cation and an ion")=(lambda^+)/(lambda)`
C ) Fraction of mole undergoing Ionisation `=("MOLAR conductance at any concentration")/("Molar conductance at infinite dilution")`
` alpha = (^^_m^(c))/(^^_m^(0)) , alpha = (^^_e^(c))/(^^_(E)^(0)`
D) Transport number of `Na^(+)` ions in NaCl ` t_(+) = ("current = carried by cation")/("current carried by cation and anion")`
`=(U^+)/(U^(+) + U^(-)) and t_(+) = (lambda^(+))/(lambda)`


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