1.

Match the following

Answer»


Solution :(a) `HCL to H^(+) + Cl^(-)`
Cathode : ` 2H^(+) + 2e^(-) to H_2`
Anode " ` 2H_2O to O_2 + 4e^(-) + 4H^(+)`(b) `NACL to Na^(+)+ Cl^(-)`
Cathode : `2H_2Oto O_2 + 2e^(-) + 4H^(+)`
Anode : `2H^(1)+ 2e^(-) to H_2`
(c) CONCENTRATED NaCl
Anode : `2Cl^(-) to Cl_2 + 2e^(-)`
Cathode : `2H^(+) +2e^(-) to H_2`(d)Anode: ` 2H_2O + O_2 + 2e^(-) + 4H^(+) to H_2 `
Cathode : `Ag^(+) + E^(-) to Ag `


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