1.

Match the following : {:((i)"88 g of CO"_(2),(a)" 0.25 mol"),((ii)" "6.02xx10^(23)" molecules of "H_(2)O,(b)"2 mol"),((iii)"5.6 litres of CO"_(2)" at STP",(c)"1 mol"),((vi)"96 g of O"_(2),"(d)"6.022xx10^(23)" molecules"),((v) "1 mol of any gas",(e)"3 mol"):}

Answer»


Solution :`"88 g CO"_(2)="88/88 mol = 2 mol. Hence, (i)-(B)."`
`6.022xx10^(23)" molecules of "H_(2)O="1 mol. Hence, (II)-(b)"`
`"5.6 L of O"_(2)" at STP = 5.6/22.4 mol = 0.25 mol. Hence, (iii)-(a)"`
`"96 go of O"_(2)=" 96/32 mol = 3 mol. Hence, (iv)-(e)."`
`"1 mol of any gas"=6.022xx10^(23)" molecules. Hence, (v)-(d)"`


Discussion

No Comment Found

Related InterviewSolutions