1.

Match the following : If k_a of HCN=5xx10^(-10), k_a of HOCN =3.2xx10^(-4), k_b of NH_3=1.8xx10^(-5), k_a of CH_3COOH=1.8xx10^(-5) (All data at 25^@ C) {:("Column-I","Column-II"),((A)10^(-2) M NaCN, (p)pH gt 7),((B)"100 ml of" 10^(-1) M NaCl + "100 ml of"10^(-1) M "HCl+300 ml of" 10^(-1)M NaOH ,(q)pH ne7),((C )10^(-1) "M HCl +" 10^(-1) "M HCN",(r)pH lt 7),((D)10^(-1) M NH_4OCN,(s)pH=7),(,(t)"pOH lt 7"):}

Answer»


Solution :(A)anionic hydrolysis LEADS to formation of `OH^(-)` due to which `pH gt7`
(B)`(N_1V_1)_(NaOH) GT (N_2V_2)_(HCL)`
( C)strong acid + weak acid, so `pH lt 7`
(D) Hydrolysis of cation leads to the formation of `H^+` due to which `pH lt 7`


Discussion

No Comment Found