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Match the following if moleculat weight of X, Y and Z are same {:(,"B.Pt.",K_(b)),("X",100,0.68),("Y",27,0.53),("Z",253,0.98):} |
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Answer» Solution :`K_(b)=(RT_(b)^(2))/(1000l_(V))=(RT_(b)^(2)M)/(1000DeltaH_(v))=(RT_(b)M)/(1000DeltaS_(v))(becauseDeltaS_(v)=(DeltaH_(v))/(T_(b)))` Where `DeltaS_(v)` is entropyo f vaporisation at the boiling point `T_(b)`. Entropy of vaporisation, `DeltaS_(v)=S_(v)-S_(L)` is almost constant. This is because though entropy of liquid `(S_(l))` VARIES from liquid to liquid but entropy of vapour `(S_(v))` is ABNORMALLY higher. As M and R are also constant, hence `K_(b) prop T_(b)`. Thus, the values reported in the table are in the correct order. |
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