Match the properties given in Colunmn I with the emtals given in Column II. {:(,"Column I (Property)",,"Column II ( Metal)"),((i),"Element with higher second ionisation enthalpy ",(a),Co),((ii) ,"Element with highest third ionisation enthalpy",(b),Cr),((iii),"M in "M(CO)_(6)"is",(c ) ,Cu),((iv),"Element with highest heat of atomisation",(d ),Zn),(,,(e ),Ni):}

Match the properties given in Colunmn I with the emtals given in Colum

1.	Match the properties given in Colunmn I with the emtals given in Column II. {:(,"Column I (Property)",,"Column II ( Metal)"),((i),"Element with higher second ionisation enthalpy ",(a),Co),((ii) ,"Element with highest third ionisation enthalpy",(b),Cr),((iii),"M in "M(CO)_(6)"is",(c ) ,Cu),((iv),"Element with highest heat of atomisation",(d ),Zn),(,,(e ),Ni):}
Answer» Solution :(i) `Cu^(+) = 3D^(10) ` which is verystable configuration . HENCE, REMOVAL of 2nd electron requires very high energy. Hence, `(i) rarr (C )`. (ii) `ZN^(2+) = 3d^(10)`. Hence, removal of 3rd electron requires very highenergy. Hence, (ii) `rarr` (d). (iii) Metal carbonyl with formula ` M (CO)_(6) `is `Cr(CO)_(6)` . Hence, (iii) `rarr` (b). (iv)Ni has highest enthalpy of atomisation . Hence, (iv)` rarr `( e )