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MATHS EX 5.2QUESTION NO3​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><ol><li>V=4πε01((r2−4a2)4a)</li></ol><h3>V=4πε01((r2−4a2)<a href="https://interviewquestions.tuteehub.com/tag/2p-300467" style="font-weight:bold;" target="_blank" title="Click to know more about 2P">2P</a>)</h3><h2>Hence, the electric <a href="https://interviewquestions.tuteehub.com/tag/potential-1161228" style="font-weight:bold;" target="_blank" title="Click to know more about POTENTIAL">POTENTIAL</a> is 4πε01((r2−4a2)2P</h2></body></html>


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