MATHS EX 5.2QUESTION NO3 – InterviewSolution

1.

MATHS EX 5.2QUESTION NO3

Answer»

V=4πε01((r2−4a2)4a)

V=4πε01((r2−4a2)2P)

Hence, the electric POTENTIAL is 4πε01((r2−4a2)2P

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