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Maths questions for class ix |
Answer» Solution :Question 1 :- Given equation : 2x + πy = 4 If y = 0 , then => 2x + πy = 4 => 2x + π•0 = 4 => 2x = 4 => X = 4/2 => x = 2 Hence , (2,0) is a solution of the given equation . °°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°° Question 2 :- Given equation : 3bx - y = 9 It is said that , (3,3) is one of the solution of the given equation . Thus , The COORDINATES of the point (3,3) must satisfy the given equation . Now , PUTTING x = 3 , y = 3 in the given equation , We have ; => 3bx - y = 9 => 3b•3 - 3 = 9 => 9b - 3 = 9 => 9b = 9 + 3 => 9b = 12 => b = 12/9 => b = 4/3 (Answer) Hence , Required value of b is 4/3 . °°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°° Question 3 :- Given equation : 2x + 3y = 18 Answer : Infinitely many solutions Reason : • If a system contains only one equation , then it has infinitely many solutions . • A straight line has infinitely many solutions as infinitely many POINTS lies on it . °°°′°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°° Question 4 :- Given equation : 3x - 4y = 12 If x = 0 , then => 3x - 4y = 12 => 3•0 - 4y = 12 => 0 - 4y = 12 => -4y = 12 => y = 12/-4 => y = -3 If y = 0 , then => 3x - 4y = 12 => 3x - 4•0 = 12 => 3x = 12 => x = 12/3 => x = 4 Hence , (0,-3) and (4,0) are two solutions of the given equation . • The equation has infinitely many solutions as Infinitely many points lies on it . • A system containing only one equation has infinitely many solutions . |
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