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maximize `Z=25x_1+20x_2` subject to constraints`3x_1+2x_2 |
Answer» `2x_1+1050=1400` `x_1=175` `700+x_2=1400` `x_2=100` `Z=25x_1+20x_2`at A(0,150) Z=0+3000=3000 at B(175,150) Z=25*175+20*150=7375 at C(350,100) Z=350*25+100*20=10750 at D(350,0) Z=350*25=8750 Z is maximum at C |
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