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Maximum acceleration of a particle in SHM is `16 cm//s^(2)` and maximum uelocity is `8 cm//s`.Find time period and amplitude of oscillations. |
Answer» Correct Answer - A::B::C::D `a_(max)=omega^(2) A=16 cm/s^2` …(i) `u_(max)= omega A = 8 cm/s` …(ii) Solving Eqs.(i) and (ii), we get `A = 4cm` and `omega = 2rad//s` Now, `T = (2pi)/(omega) = (2pi)/(2) = (pi) s` or `T~~3.14s` |
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