1.

Maximum magnetic force on electron moving with velocity 4xx10^(4)m//s is _____ when it moves in magnetic field having intensity 5xx10^(-5)T.

Answer»

`1.6xx10^(-19)N`
`3.2xx10^(-19)N`
`1.6xx10^(-17)N`
`3.2xx10^(-17)N`

Solution :From EQUATION `vecF=q(vecvxxvecB)`, MAXIMUM magnetic force on electron
F = evB
`=1.6xx10^(-19)xx4xx10^(4)xx5xx10^(-5)`
= `3.2xx10^(-19)N`


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