1.

Maxwell's modified form of Ampere's circuital law is

Answer»

`oint barB.bardl= mu_0 I`
`oint barB.bardl= mu_0 I + mu_0epsilon_0 (dphi_z)/(DT)`
`oint barB.phi s = 0`
`oint barB.bardl= mu_0 I + 1/epsilon_0 (DQ)/(dt)`

ANSWER :B


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