1.

Mean deviation for n observation x_1,x_2,……….,x_n from their mean barx is given by…….

Answer»

`sum_(i=1)^(n) (x_i = BARX)`
`1/n sum_(i=1)^(n) |x_i - barx|`
`sum_(i=1)^(n) |x_i - barx|`
`1/n sum_(i=1)^(n) (x_i - barx)^2`

ANSWER :B


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