1.

Mean lives of a radioactive substance are 1620 and 405 years for alpha and beta -emission respectively. If alpha and beta decays are simultaneous, then time during which three fourth of the sample will decay is :

Answer»

410 YEARS
442 years
449 years
512 years

Solution :`tau=(T_(1)T_(2))/(T_(1)+T_(2))=324 years`
Also half-life period
`T=0.93 tau=0.693 XX 324"years"`
But `N/N_(0)=(1/2)^(l/T)`
`1/R=(1/2)^(t//T) rArr (1/2)^(2) =(1/2)^(t//T) therefore t/t=2`
`t=2T=2 xx 0.693 xx 324=449"years"`


Discussion

No Comment Found

Related InterviewSolutions