1.

Measure of two quantities along with the precision of respective measuring instrument is `A=2.5ms^(-1)+-0.5ms^(-1)`,B=0.10s+-0.01s`. The value of AB will beA. `(0.25 +- 0.08)m`B. `(0.25 +- 0.5)m`C. `(0.25 +- 0.05)m`D. `(0.25 +- 0.135)m`

Answer» Correct Answer - a
`A = 2.5ms^(-1) +- 0.5ms^(-1) ,B = 0 10s`
`x = AB = (2.5)(0.10) = 0.25m`
`(Delta x)/(x) = (Delta A)/(A) + (Delta B)/(B)`
`(0.2)/(2.5) + (0.01)/(0.10) = (0.05 + 0.025)/(0.25) = (0.075)/(0.25)`
`Delta x = 0.075 = 0.08m`
Rounding off to two significant figure
`AB = (0.25 +- 0.08)m`


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