1.

Mechanism of a hypothetical reaction X_(2)+Y_(2)iff 2" XY" is given below : (i) X_(2)toX+X" (fast)" (ii) X+Y_(2)iff" XY"+Y" (slow)" (iii) X+Y to" XY (fast)" The overall order of reaction will be

Answer»

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`1.5`

Solution :As rate depends UPON the slowest step,
Rate `=k[X]{Y_(2)]`
Taking step (i) to be reversible ( not GIVEN),
`K_(EQ) = ([X]^(2))/([X_(2)]) or [X] = k_(eq)^(1//2) [X_(2)]^(1//2)`
Substituing in (i),
Rate `= k_(eq)^(1//2) [X_(2)]^(1//2) [Y_(2)] = k'[X_(2)]^(1//2)[Y_(2)]`
OVERALL order `= (1)/(2) + 1 = (3)/(2) = 1.5`


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