InterviewSolution
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InterviewSolution
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Mechanism of a hypothetical reaction `X_(2) + Y_(2) rarr 2XY` is given below: (i) `X_(2) rarr X + X` (fast) (ii) `X+Y_(2) hArr XY+Y` (slow) (iii) `X + Y rarr XY` (fast) The overall order of the reaction will be :A. 1B. 2C. 0D. 1.5 |
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Answer» Correct Answer - D The solution of this question is given by assuming step (i) to be reversible which is not given in question Overall rate = Rate of slowest step (ii) `=k[X][Y_(2)]`......(1) k=rate constant of step (ii) Assuming step (i) to be reversible, its equilibrium constant, `k_(eq)=([X]^(2))/([X_(2)]) implies [X]=k_(eq)^(1/2)[X_(2)]^((1)/(2))`.....(2) Put (2) in (1) Rate `=kk_(eq)^((1)/(2))[X_(2)]^((1)/(2))[Y_(2)]` Overall order `=(1)/(2)+1=(3)/(2)` |
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