InterviewSolution
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InterviewSolution
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Median of the scores 1, 3, 5, 7, 9, ……… 99 is …………A) 51 B) 50 C) 49 D) 48 |
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Answer» Correct option is: B) 50 Total number of scores is n. \(\therefore\) 2n-1 = 99 \(\Rightarrow\) 2n = 99 +1 = 100 \(\Rightarrow\) n = \(\frac {100}2 = 50 \) which is even Now, \(\frac n2 = \frac {50}2 = \) 25th & \(\frac n2 +1 = 25 +1 \) = 26th Also, 25th score = 2 \(\times\) 25 -1 = 49 26th score = 2 \(\times\) 26 -1 = 51 \(\therefore\) Median of the scores 1, 3, 5, 7......99 is the average of 25th score & 26th score (\(\because\) n = 50 is even) \(\Rightarrow\) Median = \(\frac {25th \, score + 26th\, score}{2} = \frac {49 + 51}{2} = \frac {100}2 = 50\) Hence, median of the scores 1, 3, 5 ....99 is 50. Correct option is: B) 50 |
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