InterviewSolution
Saved Bookmarks
| 1. |
Melting point of a solid is x K and its latent heat of fusion is 600 cal `mol^(-1)`. The entropy change for fusion of 1 mol solid is 2 cal `mol^(-1)K^(-1)`. The value of x will be:A. 100KB. 200KC. 300KD. 400K |
|
Answer» Correct Answer - C `(DeltaH_("fusion"))/(T_("mp"))=DeltaS_(fusion)` `(600)/(T)=2` `T=300K` |
|