1.

Melting point of a solid is x K and its latent heat of fusion is 600 cal `mol^(-1)`. The entropy change for fusion of 1 mol solid is 2 cal `mol^(-1)K^(-1)`. The value of x will be:A. 100KB. 200KC. 300KD. 400K

Answer» Correct Answer - C
`(DeltaH_("fusion"))/(T_("mp"))=DeltaS_(fusion)`
`(600)/(T)=2`
`T=300K`


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