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Metal ring of radius R is placed perpendicular to uniform magnetic field B. Magnetic field starts changing at a rate alpha |
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Answer» Electric field at any POINT on the ring is zero. `phi= piR^(2)B` Magnitude of emf induced in the loop can be written as follows: `e = dphi//dt = pi R^(2) (dB//dt)=pi R^(2) alpha` We can see that OPTION (d) is correct. Due to SYMMETRY electric field at any point on the ring is same. If E is electric field intensity, then we can multiply electric field, with length of the circle (`2piR`) to calculate induced emf. We can equate it to the calculated value of emf as follows: `E xx 2piR= pi R^(2)alpha` `E= alpha R//2` Option (b) is correct. Hence, options (b) and (d) are correct. |
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