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Method 1 of Q Temperature of two moles of a monoatomic gas is increased by 300 K in the process `p prop V`. (a) Find molar heat capacity of the gas in the given process. (b) Find heat given to the gas in that. |
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Answer» Correct Answer - A::B (a) `p prop Vimplies pV^-1=` constant If we compare with `pV^x=` constant, then `x=-1` Now, `C=C_V+(R)/(1-x)` `C_V=3/2R` for a monoatomic gas `:.` `C=3/2R+(R)/(1-(-1))=2R` (b) `Q=nCDeltaT` Substituting the values, we get `Q=(2)(2R)(300)` `=1200R` |
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