InterviewSolution
Saved Bookmarks
| 1. |
Method 2 of Q In a given process work done on a gas is 40 J and increases in its internal energy is 10J. Find heat given or taken to/from the gas in this process. |
|
Answer» Correct Answer - C Given, `DeltaU=+10J` Work done on the gas is 40 J. Therefore, work done by the gas used in the equation, `Q=W+DeltaU` will be `-40J`. Now, putting the values in the equation, `Q=W+DeltaU` We have, `Q=-40+10` `=-30J` Here, negative sign indicates that heat is taken out from the gas. |
|