1.

Methyl cyanide on reduction with sodium and alcohol gives:

Answer»

Methyl AMINE
ETHYL amine
Methyl alcohol
Acetic acid.

Solution :`CH_(3)CN+4Hoverset(Na.C_(2)H_(5)OH)RARR underset("Ethyl amine")(CH_(3)CH_(2)NH_(2))`


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