1.

Mg + Cu^(2+) to Mg^(2+) +Cu , What is E_("cell")^(0) ? E_(Mg^(2+)//Mg)^(0)=-2.36 V, E_(Cu^(2+)//Cu)^(0)=0.34 V

Answer»

`2.7 V`
2.7 V
`-2.02 V`
`2.02 V`

SOLUTION :`E_(cell)^(0)=E_(cathode)^(0)-E_(ANODE)^(0) =0.34-(-2.36)=2.7 V`


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