1.

Middle term in the expansion of `(a^(3) + ba)^(28)` is ......

Answer» Given expansion is `(a^(3) + ba)^(28)`
`:. N = 28`
`:.` Middle term `= ((28)/(2) + 1)th` term = 15 th term
`:. T_(15) = T_(14 + 1)`
`= .^(28)C_(14) (a^(3))^(28 - 14) (ba)^(14)`
`= .^(28)C_(14) a^(42) b^(14) a^(14)`
`= .^(28)C_(14) a^(56) a^(14)`


Discussion

No Comment Found

Related InterviewSolutions