1.

Minimum excitation potential of Bohr's first orbit in hydrogen atom is ...... eV

Answer»

13.6
3.4
10.2
3.6

Solution :When ELECTRON TRANSITS from orbit n = 1 to n = 2 then it get minimum excitation ENERGY.
Minimum excitation energy
`=(13.6)/(2^(2))-(-(13.6)/(1^(2)))`
`=-(13.6)/(4)+13.6`
=10.2 eV


Discussion

No Comment Found

Related InterviewSolutions