minutes partial pressure of gas in container will be4 are placed in co

1.	minutes partial pressure of gas in container will be4 are placed in container. If a hole was made in container, after 5Pdiborane> Pmethane> Phydrogen)t rtatrment among(Pco
Answer» The lighter the mass , greater will be the exit velocity. so, lesser will be the amount left in the container. and mass of CO = 28... while mass of B2H2 is 27.66 , mass of CH4 = 16 and mass of H2 = 2. so, Pco = P(diborane) > Pch4 > P(H2)

minutes partial pressure of gas in container will be4 are placed in container. If a hole was made in container, after 5Pdiborane> Pmethane> Phydrogen)t rtatrment among(Pco

Answer»

The lighter the mass , greater will be the exit velocity. so, lesser will be the amount left in the container.

and mass of CO = 28... while mass of B2H2 is 27.66 , mass of CH4 = 16 and mass of H2 = 2.

so, Pco = P(diborane) > Pch4 > P(H2)