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Mixture of two metals having mass 2 gm (A = 15, B = 30) and are bivalent and dissolve in HCl and evolve 2.24 L H_(2) at STP . What is mass of A present in mixture ? |
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Answer» 1 gm mole `=(x)/(15)""(x)/(15)` `B+2HClto BCl_(2)+H2` mole `=(2-x)/(30)""(2-x)/(30)` mole of `H_(2)=(x)/(15)+(2-x)/(30) =(2.24)/(22.4)=1/10` `(x)/(15)-(x)/(30)=1/10-1/15x=1` gm |
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