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@ Moderators @ Stars @ Best Users # Question # Two groups are competing for the position on boards of directors of a corporation . the probability that the first group and the second group will win are 0.6 and 0.4 respectively. father is the first group wins the probability of introducing a new product is 0.7 and the corresponding probability is 0.3 if the second group wins . find the probability that the new product introduced was bye second group .​

Answer»

LET

Consider F as first group, S as second group and N as introducing a NEW PRODUCT

Here we should determine

P (S/N) – New product INTRODUCED by the second group

p \: by \: s \: = \frac{p(s).p(n \: and \: s)}{p(s).p(n \: and \: s) + p(f).p(n \: and \: s)}

substitute the value

= \frac{(0.4)(0.3)}{(0.6)(0.7) + (0.4)(0.3)}

so we get

=0.12/0.54

=2/9

hence the probability of the second indrotused a new product is 2/9


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