mohit makes 8 full rounds of a rectangle field with length 120m and br

1.	mohit makes 8 full rounds of a rectangle field with length 120m and breadth 75m john make 10 full rounds of a square field with each side 100m find who covers larger distance and by how much
Answer» GIVEN: Length of Rectanglular field = 120 m Breadth of Rectanglular field = 75 m Sides of square field = 100 m To find: Who covers larger distance and by how MUCH? SoluTion: As per given Question, MOHIT makes 8 full rounds of a rectangle field. As we know that, ★ Perimeter of Rectangle = 2(l + b) Distance covered by Mohit in one round = Perimeter of rectangular field $\implies$ 2(120 + 75) $\implies$ 2(195) $\implies$ 390 m Therefore, Mohit covers 390 m to complete 1 round. So, Distance covered by Mohit to complete 8 round is, $\implies$ 8 × 390 $\implies$ 3120 m ━━━━━━━━━━━━━━━ Now, In case of John, John make 10 full rounds of a square field. As we know that, ★ Perimeter of Square = 4 × side Distance covered by John in one round = Perimeter of square field $\implies$ 4 × 100 $\implies$ 400 m Therefore, John covers 400 m to complete 1 round. So, Distance covered by John to complete 10 round is, $\implies$ 400 × 10 $\implies$ 4000 m Therefore, we can say that John covers greater distance than Mohit. John covers greater distance than Mohit by, $\implies$ 4000 - 3120 $\implies$ 480 m $\rule{170}2$ ★ Additional Information: Area of Rectangle = l × b Area of Square = side × side

mohit makes 8 full rounds of a rectangle field with length 120m and breadth 75m john make 10 full rounds of a square field with each side 100m find who covers larger distance and by how much

Answer»

GIVEN:

Length of Rectanglular field = 120 m

Breadth of Rectanglular field = 75 m

Sides of square field = 100 m

To find:

Who covers larger distance and by how MUCH?

SoluTion:

As per given Question,

MOHIT makes 8 full rounds of a rectangle field.

As we know that,

★ Perimeter of Rectangle = 2(l + b)

Distance covered by Mohit in one round = Perimeter of rectangular field

$\implies$ 2(120 + 75)

$\implies$ 2(195)

$\implies$ 390 m

Therefore, Mohit covers 390 m to complete 1 round.

So, Distance covered by Mohit to complete 8 round is,

$\implies$ 8 × 390

$\implies$ 3120 m

━━━━━━━━━━━━━━━

Now, In case of John,

John make 10 full rounds of a square field.

As we know that,

★ Perimeter of Square = 4 × side

Distance covered by John in one round = Perimeter of square field

$\implies$ 4 × 100

$\implies$ 400 m

Therefore, John covers 400 m to complete 1 round.

So, Distance covered by John to complete 10 round is,

$\implies$ 400 × 10

$\implies$ 4000 m

Therefore, we can say that John covers greater distance than Mohit.

John covers greater distance than Mohit by,

$\implies$ 4000 - 3120

$\implies$ 480 m

$\rule{170}2$

★ Additional Information:

Area of Rectangle = l × b

Area of Square = side × side