Molality of pure gas A is (50)/(1.2)m. Then molar mass (in gm/mol) of – InterviewSolution

1.	Molality of pure gas A is (50)/(1.2)m. Then molar mass (in gm/mol) of gas will be:
Answer» SOLUTION :`m=(n_(A)xx1000)/(W_(A)(gm))=(W_(A))/(M.Wt._(A))XX(1000)/(W_(A))=(1000)/(M.Wt._(A))` `(50)/(12)=(1000)/(M.Wt._(A))=(24)/(3)=8`

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