Molar conductivity of an electrolyte is the conductance of all the ions produced by one gram mole of the electrolyte in solution and is denoted as Lambda_(m). Lambda_(m)=(kxx1000)/(c ) Here k is the specific conductance while c is the molar concentration of the electrolyte. The molar conductance of the strong electrolytes at infinite dilution (Lambda_(m)^(oo)) can be obtained graphically by extrapolation while the same for weak electrolytes cannot be obtained graphically. It can be calculated theoretically with the help of Kohrausch's. Law. Lambda_(m(AxBy))^(oo)=xlambda_(m (A^(y+)))^(oo)+ylambda_(m(B^(x)))^(oo) Equivalent conductance of 1 M methanoic acid solution is 10" ohm"^(-1)cm^(2)" equiv"^(-1) and at infinite dilution it is 200" ohym"^(-1)cm^(2)" equiv"^(-1). The pH of methanoic acid solution is :

Molar conductivity of an electrolyte is the conductance of all the ion

1.	Molar conductivity of an electrolyte is the conductance of all the ions produced by one gram mole of the electrolyte in solution and is denoted as Lambda_(m). Lambda_(m)=(kxx1000)/(c ) Here k is the specific conductance while c is the molar concentration of the electrolyte. The molar conductance of the strong electrolytes at infinite dilution (Lambda_(m)^(oo)) can be obtained graphically by extrapolation while the same for weak electrolytes cannot be obtained graphically. It can be calculated theoretically with the help of Kohrausch's. Law. Lambda_(m(AxBy))^(oo)=xlambda_(m (A^(y+)))^(oo)+ylambda_(m(B^(x)))^(oo) Equivalent conductance of 1 M methanoic acid solution is 10" ohm"^(-1)cm^(2)" equiv"^(-1) and at infinite dilution it is 200" ohym"^(-1)cm^(2)" equiv"^(-1). The pH of methanoic acid solution is :
Answer» 7 3.3 1.3 6.8. Solution :(c ) `alpha=(Lambda_(m)^(c ))/(Lambda_(m)^(prop))=((10" OHM"^(-1) cm^(2) " equiv"^(-1)))/((200" ohm"^(-1) cm^(2)" equiv"^(-1)))=0.05` `[H^(+)]= C alpha=1Mxx0.05=0.05 M` `pH=-LOG [H^(+)]=-log(0.05)` `=-log(5xx10^(-2))=(2-log 5)` =2-0.6990=1.3