1.

Molar conductivity of Ba^(2+) and Cl^(-1) ions present in aqueous solution of BaCl_(2) are 127.32"S"cm^(2)mol^(-1) and 76.34" S "cm^(2)mol^(-1) respectively, then what is Lamda_(m) of BaCl_(2) solutioin ?

Answer»

`280" S "CM^(2)mol^(-1)`
`330.98" S "cm^(2)mol^(-1)`
`90.98" S "cm^(2)mol^(-1)`
`203.6" S "cm^(2)mol^(-1)`

Solution :`Lamda_(m)(BaCl_(2))=lamda(BA^(2+))+2lamda(Cl^(-))`
`=127.32+2xx76.34`
`=280" S "cm^(2)mol^(-1)`.


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