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Molar heat capacity of `CD_(2)O` (deuterated form of formaldehyde) at constant pressure in `9 cal mol^(-1) K^(-1) at 1000K`. Calculate the entropy change associated with cooling of `3.2 g` of `CD_(2)O` vapour from `1000 to 900K`. |
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Answer» `DeltaH` for cooling `CD_(2)O = mS DeltaT = (3.2)/(32) xx 9 xx 100 = 90 cal` Therefore, cooling is exothermic, `DeltaH =- 90 cal` Now, `DeltaS = (DeltaH)/(T) = - (90)/(900) =- 0.1 cal deg^(-1)` |
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