1.

Molar heat capacity of ethenol is 110.4 JK^(-1) mol^(-1). Its specific heat capacity is

Answer»

2.4
55.2
5.078 kJ
110.4

Solution :Specific heat capacity = `("MOLAR heat capacity")/("Molar mass")`
`= (110.4 JK)/(46)`
`= 2.4 JK^(-1) mol^(-1)`


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