1.

Molarity of aqueous glucose (C_(6)H_(12)O)^(6) will be, if mole fraction of glucose is 0.4.

Answer»

10M
3.7M
0.4M
2M

Solution :`n_("glucose")=0.4rArrw_("glucose")=0.4xx180=72(M WT. C_(6)H_(12)O_(6)=180)`
`n_(H_(2)O)=0.6rArrW_(H_(w)O)=0.6xx18=18.8`
`W_("solution")=72+10.8=82.8gm`
`d_("solution")=(82.8)/(V_("solution"))=2.07 gm//mlrArrV_("solution")=(82.8)/(2.07)=40ml`
Molarity `rArrM=(0.4)/(40)xx1000=10M`


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