1.

Mole fraction of vapour of `A` above solution in mixture of `A` and `B(X_(A) = 0.4)` will be `(P_(A)^(@) = 100mm, P_(B)^(@) = 200 mm)`:A. 0.4B. 0.25C. 0.85D. None of these

Answer» Correct Answer - B
Mole fraction of A in vapour phase
`=(p_(A)^(@)x_(A))/(p_("Total"))=(100xx10^(0.4))/(100xx4+200xx0.6)=0.25`


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