1.

Mole fraction of x M aqueous urea solution is : [Given : density of solution is d gm//ml ]

Answer»

`(18x)/(1000d - 42 x)`
`(18 x)/(1000d - 60x)`
`(18x)/(1000d - 18x)`
None of these

Solution :x MOLES of Urea in 1000 ml of solution
mass of solution = 1000 d gm
mass of solute `60 x gm`
mass of solvent `= (1000d - 60x) gm`
MOLE fracction of urea `= (x)/(x + ((1000d - 60x)/(18)))`
`= (18x)/(18x + 1000d - 60x)`
`x_("urea") = (18x)/(1000d - 42X)`


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