1.

Mole fration of a solute in 2.0 molal aqueous solutions is :

Answer»

1.77
1.87
0.0347
0.347

Solution :`"Mole fraction of solute"(X_(B))=n_(B)/(n_(B)+n_(A))`
`"No, of moles of solute"(n_(B))=2 MOL`
`"No. of MOELS of WATER"(n_(A))=((1000g))/((18g mol^(-1)))`
=55.55 mol
`X_(B)=((2 mol))/((57.55 mol))=0.0347`


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