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Molefractionof urea in itsaqueous solution is 0.25 .Whatis themassof ureapresentin 200 gureasolution? (Molecularmass of ureais 60 g mol^(-1))

Answer»


Solution :GIVEN : Mole fractionof UREA = 0.25
Mass ofureain 200 gsolution = ?
Molefractionof water= 1- 0.25 =0.75
Massof urea= 0.25 `xx 60 =15 g`
Massof water= 0.75 `xx 100= 75 g`
`:.` Massof solution= 15+75 = 90 g
`:.` 90 g solutioncontains15 gurea
`:.200`g solutionwillcontain `(200 xx 15)/(90) ` = 33.33 g urea


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