1.

moles of an ideal gas expand isothermallty anad reversibly from pressure of 5 atm to 1 atm at 300 K . Calculate the largest mass than can be lifted through a height of 1 M by this expansion .

Answer»

4092.76 KG
8730.9368 kg
4492.76 kg
8170.2344 kg

Solution :`W_(exp)=-2.303nRTlogP_(1)//P_(2)`
` 2.303xx 20 XX 8.314 JK^(-1)MOL^(-1)xx300 K log 5/1`
`80.15 xx 10^(3 J)`
work done = mgh
`80.15 xx 10^(3) = m xx 9.81 ms^(-2) xx1m`
` m = (80.15xx10^(3) KGM^(2)s^(-2))/(9.81 ms ^(-2)xx1m) = 8.17023xx10^(3)`
` 8170 . 2344 kg `


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