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moles of an ideal gas expand isothermallty anad reversibly from pressure of 5 atm to 1 atm at 300 K . Calculate the largest mass than can be lifted through a height of 1 M by this expansion .A. 4092.76 kgB. 8730.9368 kgC. 4492.76 kgD. 8170.2344 kg |
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Answer» Correct Answer - d `W_(exp)=-2.303nRTlogP_(1)//P_(2)` ` 2.303xx 20 xx 8.314 JK^(-1)mol^(-1)xx300 K log 5/1` `80.15 xx 10^(3 J)` work done = mgh `80.15 xx 10^(3) = m xx 9.81 ms^(-2) xx1m` ` m = (80.15xx10^(3) kgm^(2)s^(-2))/(9.81 ms ^(-2)xx1m) = 8.17023xx10^(3)` ` 8170 . 2344 kg ` |
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