InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Moment of inertia of a body about a given axis is the rotational inertia of the body about that axis. It is respresented by `I = MK^(2)`, where `M` is mass of body and `K` is radius of gyration of the body about that axis. It is a scalar quantity, which is measured in `kg m^(2)`. when a body rotates about a given axis, and teh axis of rotates also moves, then total `K.E.` of body `= K.E.` of translation `+ K.E.` of rotation `E = (1)/(2)mv^(2) + (1)/(2)I omega^(2)` Which the help of the compreshension given above, choose the most apporpriate altermative for each of the following questions : A `40 kg` flywheel in the from of a unifrom circular disc of diameter `1 m` is making `120 rpm`. Its moment of inertia about a transverse axis through its centre isA. `40 kg m^(2)`B. `5 kg m^(2)`C. `10 kg m^(2)`D. `20 kg m^(2)` |
|
Answer» Correct Answer - B `I = (1)/(2)MR^(2) = (1)/(4) xx 40 ((1)/(2))^(2) = 5 kg m^(2)` |
|