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| 1. |
Moment of inertia of a uniform rod of length `L` and mass `M`, about an axis passing through `L//4` from one end and perpendicular to its length isA. `(7)/(36)ML^(2)`B. `(7)/(48)ML^(2)`C. `(11)/(48)ML^(2)`D. `(ML^(2))/(12)` |
| Answer» `I=(ML^(2))/(12)+M((L)/(4))^(2)=(7)/(48)ML^(2)` | |