InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Momentum of a particle is increased by `50%`. By how much percentage kinetic energy of particle will increase?A. `25%`B. `50%`C. `100%`D. `125%` |
|
Answer» Correct Answer - B We know that `K prop P^(2)` or `(K_(2))/(K_(1)) = (P_(2)^(2))/(P_(1)^(2))` `(K_(2) - K_(1))/(K_(1)) xx 100 = ((P_(2)^(2) - P_(1)^(2))/(P_(1)^(2))) xx 100` `= [((150)^(2) - (100)^(2))/((100)^(2))] xx 100 = 125%` |
|